Herpes

Question by jayteemoney: My code will build successfully but my debugging says other wise – whats wrong here?
I’m trying to build a 10 question quiz and I’m designing it to where if you get the write answer it will move to the next question.

the problem I’m having is its saying (a,b,c,d,) is not initialized to anything when I clearly have initialized it as far as I need

Why is it telling me this?

#include
using namespace std;

int main()
{

char Answer;
char a, b, c, d;

cout<<"you will be givin a short Exam of 10 questions \n"< cout<<"Press enter after each question is answered \n"< cout< cout< do
{
cout<<"Question 1"< cout<<"where was Jason Born? \n\n"< cout< cout<<"(a) - Chicago?"< cout<<"(b) - Atlanta?"< cout<<"(c) - Pheonix?"< cout<<"(d) - Tucson?" < cin>>Answer;
cin.sync();
cin.get();

if (Answer==d)
{
cout<<"Thats Correct!"< }
else
cout<<"Try Again"< }while (Answer==a,b,c);

return 0;
}

//also should I be using bool instead of if else?

Best answer:

Answer by Axis
char Answer =”";
char a, b, c, d = “”;

Initializing variables means giving them a value (even if it is null) when you first create the variable.

Add your own answer in the comments!
Question by jabaroni: help with a program code in c++?
I am trying to create an array of the tempatures listed in the main. The first one “Miami” shows up, but I cant get the other ones to show and they need to be in the form of an array. Im stuck. Help! please.

// Temperatureproblem.cpp : Defines the entry point for the console application.
//

#include “stdafx.h”
#include
#include

using namespace std;

class Temperature
{

private:
string average;
string location;
int high;
int low;
int measure;

public:

Temperature(string Location, int High, int Low, int Measure){
location = Location;
high = High;
low = Low;
measure = Measure;
}

int getAverage(){
return((high + low) / 2);
}

void displayTemp(){

cout << location << "\t" << high << "\t" << low << "\t" << getAverage() << endl;

}

};

int _tmain(int argc, _TCHAR* argv[])
{
Temperature temp = Temperature("Miami", 35, 29, 0);
Temperature temp = Temperature("Ft. Lauderdale", 90, 80, 0);
Temperature temp = Temperature("Washington, D.C.", 29, 16, 0);
Temperature temp = Temperature("New York", 32, 21, 0);
Temperature temp = Temperature("Cincinnati", 85, 63, 0);
Temperature temp = Temperature("Chicago", 28, 20, 0);
Temperature temp = Temperature("Las Vegas", 92, 79, 0);
Temperature temp = Temperature("Los Angeles", 89, 77, 0);
Temperature temp = Temperature("Seattle", 29, 15, 0);
temp.displayTemp();
return 0;
}

Best answer:

Answer by Paul
temp needs to be an array – at the moment you just have a single temperature object which you keep over-writing.

Temperature *temp[10];
temp[0] = new Temperature(“Miami”, 35, 29, 0);
temp[1] = new Temperature(“Ft. Lauderdale”, 90, 80, 0);
// etc…

What do you think? Answer below!